### MATHEMATICS FORM FOUR TOPIC 5: TRIGONOMETRY

Sunday, January 22, 2023

Form Four
MATHEMATICS
## MATHEMATICS FORM FOUR TOPIC 5: TRIGONOMETRY

**TRIGONOMETRY**

Trigonometric Ratios

The Sine, Cosine and Tangent of an Angle Measured in the Clockwise and Anticlockwise Directions

The Sine, Cosine and Tangent of an Angle Measured in the Clockwise and Anticlockwise Directions

Consider the following right angled triangle.

Also we can define the above triangle ratios by using a unit Circle centered at the origin.

If θis an obtuse angle (900<θ<180 style="box-sizing: border-box;" sup="">0

If θis a reflex angle (1800< θ<270 style="box-sizing: border-box;" sup="">0) then the trigonometrical ratios are the same as that of θ- 1800

If θis a reflex angle (2700< θ< 3600), then the trigonometrical ratios are the same as that of 3600 -θ

We have seen that trigonometrical ratios are positive or negative depending on the size of the angle and the quadrant in which it is found.

The result can be summarized by using the following diagram.

**Trigonometric Ratios to Solve Problems in Daily Life**

**Example 1**

**Write the signs of the following ratios**

Sin 1700

Cos 2400

Tan 3100

sin 300

Solution

a)Sin 1700

Since 1700 is in the second quadrant, then Sin 1700 = Sin (1800-1700) = Sin 100

∴Sin 1700 = Sin 100

b) Cos 2400 = -Cos (2400-1800)= -Cos 600

Therefore Cos 2400= -Cos 600

c) Tan 3100 = -Tan (3600-3100) = - Tan 500

Therefore Tan 3100= -Tan 500

d) Sin 3000= -sin (3600-3000) = -sin 600

Therefore sin 3000= - Sin 600

Relationship between Trigonometrical ratios

The above relationship shows that the Sine of angle is equal to the cosine of its complement.

Also from the triangle ABC above

Again using the ΔABC

b2 = a2+c2 (Pythagoras theorem)

And

**Example 2**

**Given thatA is an acute angle and Cos A= 0.8, find**

Sin A

tan A

**Example 3**

**If A and B are complementary angles,**

Solution

If A and B are complementary angle

Then Sin A = Cos B and Sin B = Cos A

**Example 4**

**Given that θand βare acute angles such that θ+ β= 900 and Sinθ= 0.6, find tanβ**

Solution

**Exercise 1**

For practic

**Sine and Cosine Functions**

Sines and Cosines of Angles 0 Such That -720°≤ᶿ≥ 720°

Positive and Negative angles

An angle can be either positive or negative.

Definition:

Positive angle: is an angle measures in anticlockwise direction from the positive X- axis

Negative angle: is an angle measured in clockwise direction from the positive X-axis

Facts:

An angle can be either positive or negative.

Definition:

Positive angle: is an angle measures in anticlockwise direction from the positive X- axis

Negative angle: is an angle measured in clockwise direction from the positive X-axis

Facts:

From the above figure if is a positive angle then the corresponding negative angle to is (- 3600) or (+ - 3600)

.If is a negative angle, its corresponding positive angle is (360+)

**Example 5**

**Find thecorresponding negative angle to the angle θif ;**

θ= 580

θ= 2450

**Example 6**

What is the positive angle corresponding to - 46°?

SPECIAL ANGLES

The angles included in this group are 00, 300, 450, 600, 900, 1800, 2700, and 3600

Because the angle 00, 900, 1800, 2700, and 3600, lie on the axes then theirtrigonometrical ratios are summarized in the following table

Because the angle 00, 900, 1800, 2700, and 3600, lie on the axes then theirtrigonometrical ratios are summarized in the following table

The ∆ ABC is an equilateral triangle of side 2 units

For the angle 450 consider the following triangle

The following table summarizes the Cosine, Sine, and tangent of the angle 300 , 450 and 600

**The following figure is helpful to remember the trigonometrical ratios of special angles from 0°to 90°**

*NB:*If we need the sines of the above given angles for examples, we only need to take the square root of the number below the given angle and then the result is divided by 2.

**Example 7**

**Find the sine,cosine and tangents of each of the following angles**

-1350

1200

3300

**Example 8**

**Find the value of θif Cos θ= -½ and θ≤ θ≤ 360°**

Solution

Since Cos θis – (ve), then θlies in either the second or third quadrants,

Now - Cos (180 –θ= - Cos (θ+1800) = -½= -Cos600

So θ= 1800-600 = 1200 or θ= 1800 + 600 = 2400

θ= 1200 0r θ=2400

**Example 9**

Consider below

**Exercise 2**

Solve the Following.

**The Graphs of Sine and Cosine**

Consider the following table of value for y=sinθ where θranges from - 360°to 360°

For cosine consider the following table of valuesFrom the graphs for the two functions a reader can notice that sinθand cosθboth lie in the interval -1 and 1 inclusively, that is -1≤sinθ1 and -1≤cosθ≤1 for all values of θ.

The graph of y= tanθis left for the reader as an exercise

NB: -∞≤ tanθ≤∞the symbol ∞means infinite

Also you can observe that both Sinθnd cosθrepeat themselves at the interval of

360°, which means sinθ= sin(θ+360) = sin(θ+2x3600) etc

and Cosθ=(Cosθ+3600)= Cos(θ+2x3600)

Each of these functions is called a period function with a period 3600

1. Usingtrigonometrical graphs in the interval -3600≤θ≤3600

Find θsuch that

Sin= 0.4

Cos= 0.9

solution

The graph of y= tanθis left for the reader as an exercise

NB: -∞≤ tanθ≤∞the symbol ∞means infinite

Also you can observe that both Sinθnd cosθrepeat themselves at the interval of

360°, which means sinθ= sin(θ+360) = sin(θ+2x3600) etc

and Cosθ=(Cosθ+3600)= Cos(θ+2x3600)

Each of these functions is called a period function with a period 3600

1. Usingtrigonometrical graphs in the interval -3600≤θ≤3600

Find θsuch that

Sin= 0.4

Cos= 0.9

solution

**Example 10**

**Use the graph of sinθto find the value ofθif**

4Sinθ= -1.8 and -3600 ≤θ≤3600

Solution

4Sinθ= -1.8

Sinθ= -1.8÷4 = -0.45

Sinθ= -0.45

So θ= -1530, -270, 2070, 3330

**The graphs of sine and cosine functions**

**Example 11**

**Use thetrigonometrical function graphs for sine and cosine to find the value of**

Sin (-400)

Cos (-400)

Solution

Sin (-400)= - 0.64

Cos (-400)= 0.76

**Sine and Cosine Rules**

The Sine and Cosine Rules

Consider the triangle ABC drawn on a coordinate plane

From the figure above the coordinates of A, B and C are (0, 0), (c, 0) and(bCosθ, bSinθ) respectively.

Now by using the distance formula

SINE RULE

Consider the triangle ABC below

Consider the triangle ABC below

From the figure above,

Note that this rule can be started as “In any triangle the side are proportional to the Sines of the opposite angles”

**The Sine and Cosine Rules in Solving Problems on Triangles**

**Example 12**

**Find the unknown side and angle in a triangle ABC given that**

a= 7.5cm

c= 8.6cm and C= 80°

Find the unknown sides and angle in a triangle ABC in which a= 22.2cmB= 86°and A= 26°

Solution

By sine rule

Sin A= sin B= Sin C

Solution

By sine rule

Sin A= sin B= Sin C

**Example 13**

**Find unknown sides and angles in triangle ABC**

Where a=3cm, c= 4cm and B= 30°

**Solution**

By cosine rule,

**Example 14**

Find the unknown angles in the following triangle

**Exercise 3**

1. Given thata=11cm, b=14cm and c=21cm, Find the Largest angle of ΔABC

2. If ABCD is a parallelogram whose sides are 12cm and 16cm what is the length of the diagonal AC if angle B=119°?

3. A and B are two ports on a straight Coast line such that B is 53km east of A. A ship starting from A sails 40km to a point C in a direction E65°N. Find:

The distance a of the ship from B

The distance of the ship from the coast line.

4. Find the unknown angles and sides in the following triangle.

5. A rhombus has sides of length 16cm and one of its diagonals is 19cm long. Find the angles of the rhombus.

**Compound Angles**

The Compound of Angle Formulae or Sine, Cosine and Tangent in Solving Trigonometric Problems

The aim is to express Sin (α±β) and Cos (α±β) in terms of Sinα, Sinβ, Cosαand Cosβ

Consider the following diagram:

Consider the following diagram:

From the figure above

From ΔBCD

For Cos(α±β) Consider the following unit circle with points P and Q on it such that OP,makes angleα with positive x-axis and OQ makes angle βwith positive x-axes.

Sin150°

Cos 15°

1. Withoutusing tables, find:

Sin 15°

Cos 120°

2. Find Sin 225° from (180°+45°)

3. Verify that

Sin 90° = 1 by using the fact that 90°=45°+45°

Cos90°=0 by using the fact that 90°=30°+60°

4. Express each of the following in terms of sine, cosine and tangent of acute angles.

Sin107°

Cos300°

5. By using the formula for Sin (A-B), show that Sin (90°-C)=Cos C

From the figure above the distance d is given by

In general

**Example 16**

**Find:**

Sin150°

Cos 15°

**Exercise 4**

1. Withoutusing tables, find:

Sin 15°

Cos 120°

2. Find Sin 225° from (180°+45°)

3. Verify that

Sin 90° = 1 by using the fact that 90°=45°+45°

Cos90°=0 by using the fact that 90°=30°+60°

4. Express each of the following in terms of sine, cosine and tangent of acute angles.

Sin107°

Cos300°

5. By using the formula for Sin (A-B), show that Sin (90°-C)=Cos C

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